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請問微積分問題
以上三題不會做 求解
謝謝
<div></div> 2. let u=tan^{-1}(y) then \int_{-1}^{1}\frac{e^{tan^{-1}(y)}{1+y^2}dy
=\int_{-\pi/4}^{\pi/4}e^udu http://www03.eyny.com/thread-8254055-1-1.html
第二題, 7 天前不是做了給你看嗎??
你如果有什麼不懂, 你應該詳細指出你不懂什麼...
這些數都是大學程度了...而第二題只屬於中學程度, 而且是最最最基本的積分問題...
你如果連第二題都不懂得如何解答, 那麼我們又怎能讓你明白第一題呢??? http://latex.codecogs.com/gif.latex?\begin{align*}\int_{0}^{1}\int_{y}^{1}\frac{\sin%20x}{x}\;dxdy&=\int_{0}^{1}\int_{0}^{x}\frac{\sin%20x}{x}\;dydx\\&=\int_{0}^{1}\begin{bmatrix}\frac{y\sin%20x}{x}\end{bmatrix}_{0}^{x}\;dx\\&=......\end{align*} http://latex.codecogs.com/gif.latex?\\W=\int_CF\;dr$%20,%20where%20where%20$C$%20is%20any%20path$\\\\$However,%20this%20integral%20is%20independent%20of%20path,%20because%20:%20$\\\\\frac{\partial%20}{\partial%20x}(-xe^{-y})=-e^{-y}=\frac{\partial%20}{\partial%20y}(e^{-y})%20\\\\$So,%20there%20exists%20$f$%20such%20that%20$F=\triangledown%20f%20$%20,%20Since%20:%20$\\\begin{align*}W=\int_CF\;dr&=\int_C\triangledown%20f\;dr\\&=\int_C(e^{-y}\;dx-xe^{-y}\;dy)\\&=\begin{bmatrix}2xe^{-y}%20\end{bmatrix}_{(2,0)}^{(0,1)}\\&=......%20\end{align*}...<div class='locked'><em>瀏覽完整內容，請先 <a href='member.php?mod=register'>註冊</a> 或 <a href='javascript:;' onclick="lsSubmit()">登入會員</a></em></div><br><br><br><br><br><div></div> chongwaikei 發表於 2012-11-16 09:54 AM static/image/common/back.gif
http://www03.eyny.com/thread-8254055-1-1.html
第二題, 7 天前不是做了給你看嗎??
謝謝
我懂了
(有點死腦筋:L)
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